What is the solution to the following equation? x^2-3x-10=0

A = x=5 or x=-2

B = x=2 or x=-5

C = x=2 or x=5

D = x=-2 or x=-5

x^2 - 3x - 10 = 0

Find two numbers when added together = - 3 and when multiplied = - 10

-5 + 2 = - 3

-5 * 2 = - 10

Now write the factored form of the equation: (x-5) (x+2) = 0

Solve for each x so that the equation = 0:

5 - 5 = 0

-2 + 2 = 0

So X = - 2 or 5

The answer is A.

A = x=5 or x=-2

Step-by-step explanation:

x^2-3x-10=0

Factor

What 2 numbers multiply together to give you - 10 and add together to give you - 3

-5*2 = - 10

-5+2 = - 3

(x-5) (x+2) = 0

Using the zero product property

x-5 = 0 x+2 = 0

x-5+5=0+5 x+2-2=0-2

x=5 x=-2