Identify the center and radius for the equation x ^ 2 + (y - 3) ^ 2 = 4

Question

Mathematics

Joan

30 January, 11:44

Identify the center and radius for the equation x ^ 2 + (y - 3) ^ 2 = 4

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Answers (1)

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Kinsley · Answer 1

r = 2. The center is at (0, 3).

Step-by-step explanation:

Compare the given x ^ 2 + (y - 3) ^ 2 = 4 to the standard equation

(x - h) ^2 + (y - k) ^2 = r^2.

It becomes obvious that h = 0, k = 3 and r = 2. The center is at (0, 3).