Factor completely.

-2k - k 3 - 3k 2

A: k (-k + 1) (k - 2)

B: - k (k - 1) (k - 2)

C: - k (k + 1) (k + 2)

Question

Mathematics

Rowan Lyons

9 December, 01:54

Factor completely.

-2k - k 3 - 3k 2

A: k (-k + 1) (k - 2)

B: - k (k - 1) (k - 2)

C: - k (k + 1) (k + 2)

+3

Answers (1)

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Pepper · Answer 1

Answer:Multiply to see that this is true. A second check is also necessary for factoring - we must be sure that the expression has been completely factored. In other words, "Did we remove all common factors? Can we factor ...

Step-by-step explanation:

Multiply to see that this is true. A second check is also necessary for factoring - we must be sure that the expression has been completely factored. In other words, "Did we remove all common factors? Can we factor ...

Factor completely.-2k - k 3 - 3k 2A: k (-k + 1) (k - 2)B: - k (k - 1) (k - 2)C: - k (k + 1) (k + 2)

Factor completely.

-2k - k 3 - 3k 2

A: k (-k + 1) (k - 2)

B: - k (k - 1) (k - 2)

C: - k (k + 1) (k + 2)