Which ordered pair is a solution to the system of equations? Use any method to solve. 4x-y=5, x+y=10

(3,7)

Step-by-step explanation:

Given equations are

4x-y = 5 eq (1)

x+y = 10 eq (2)

we have to solve the system of equations by find an ordered pair.

we use substitution method to find solution of system of equations.

From eq (2)

y = 10-x

Putting above equation in eq (2), we get

4x - (10-x) = 5

4x-10+x=5

4x+x-10=5

Add like terms

5x-10=5

Adding 10 to both sides of above equation, we get

5x-10+10 = 5+10

5x=15

Dividing by 5 to both sides of above equation, we get

5x/5 = 15/5

x = 3

Putting the value of x in eq (2), we get

3+y=10

Adding - 3 to both sides of above equation, we get

-3+3+y=-3+10

0+y = 7

y = 7

Hence, (3,7) is solution of given system of equation.

The ordered pair (5, 15) is a solution to the system of given equations.

Step-by-step explanation:

Consider the given equations,

4x-y=5 ... (1)

x+y=10 ... (2)

We have to find the ordered pair which is a solution to the system of given equations.

We solve the system by elimination method,

Adding both equation, to eliminate y,

⇒ 4x - y + (x+y) = 5 + 10

⇒ 4x - y + x + y = 15

⇒ 5x = 15

⇒ x = 5

Put x = 5 in equation (1), and solve for y,

We get,

4x - y = 5 ⇒ 4 (5) - y = 5 ⇒ y = 20 - 5 ⇒ y = 15

Thus, the ordered pair (5, 15) is a solution to the system of given equations.