Write in intercept form

y=-x^2-x+6

a. y = - (x+2) (x-6)

b. y = - (x-2) (x+3)

c. y = - (x+2) (x+6)

d. y = (-x+3) (x-4)

-x² - x + 6

First thing I would do is distribute out that negative. Your new problem is:

- (x² + x - 6)

Now, factor the inside. We need to find products of - 6 that when added together have a sum of positive 1. They are 3 and - 2.

- (x² + 3x - 2x - 6)

Group together and find your factors. I'm going to short cut and go right to them for the sake of space and time.

- (x + 3) (x - 2)

Your answer is Option B