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10 March, 15:07

A triangle has side lengths measuring 2x + 2 ft, x + 3 ft, and n ft.

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  1. 10 March, 17:11
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    Answer: x - 1 < n < 3x + 5

    Step-by-step explanation:In a triangle sum of any two sides is always greater than the third side.

    Now, the sides of the triangle are given to be:

    2x + 2, x + 3, n

    Now, first take 2x + 2 and x + 3 as two sides and the side of length n as third side.

    By using the property that sum of two sides is always greater than the third side in a triangle.

    ⇒ 2x + 2 + x + 3 > n

    ⇒ 3x + 5 > n ... (1)

    Now, take n and x + 3 as two sides and the side of length 2x + 2 as the third side of triangle.

    So, by the property, we have:

    n + x + 3 > 2x + 2

    ⇒ n > x - 1 ... (2)

    From both the equations (1) and (2), We get:

    x - 1 < n < 3x + 5

    Therefore, The answer is x - 1 < n < 3x + 5
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