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25 July, 12:38

Find the fourth term of the expansion (5 + 3y) ^5

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  1. 25 July, 16:01
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    (r+1) the term of (a + b) ^n

    = nCr a^ (n-r) b^r

    So 4th term = (3 + 1) th term) of (5 + 3y) ^5=

    5C3 (5^ (5-3) (3y) ^3

    = 10 * 25 * 27y^3

    = 6750 y^3 answer
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