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18 December, 23:09

A Statistics class is estimating the mean height of all female students at their college. They collect a random sample of 36 female students and measure their heights. The mean of the sample is 65.3 inches. The standard deviation is 5.2 inches. Use the T-distribution Inverse Calculator applet to answer the following question. What is the 90% confidence interval for the mean height of all female students in their school?

a. (56.5, 74.1)

b. (63.6, 67.0)

c. (63.8, 66.8)

d. (63.9, 66.7)

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  1. 19 December, 00:32
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    d. (63.9, 66.7)

    Therefore at 90% confidence interval (a, b) = (63.9, 66.7)

    Step-by-step explanation:

    Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

    The confidence interval of a statistical data can be written as.

    x+/-zr/√n

    Given that;

    Mean x = 65.3

    Standard deviation r = 5.2

    Number of samples n = 36

    Confidence interval = 90%

    z (at 90% confidence) = 1.645

    Substituting the values we have;

    65.3+/-1.645 (5.2/√36)

    65.3+/-1.645 (0.866667)

    65.3+/-1.42567

    65.3+/-1.4

    = (63.9, 66.7)

    Therefore at 90% confidence interval (a, b) = (63.9, 66.7)
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