A scientist is investigating a cell. The cell has a membrane thickness of 7.*10-8 m and has a surface area of 4.*10-8. The initial concentration inside the cell is n (0) = 0.6 M, and the scientist later observes that an (0.2) = 0.77 M. Assume that the concentration outside the cell is 1. M and that it will not change appreciably as the compound in the cell undergoes diffusion. What is the value of the parameter k in the equation for Fick's Law

Step-by-step explanation:

we will begin with a step by step process to make this as concise as possible.

From our basic knowledge of Fick's Law of diffusion

we have that;

dm/dt = KA (m₀-m) / x

given that m = concentration at t

m₀ = outside concentration (1)

A = area (4 * 10-8)

x = thickness (7 * 10-8)

therefore we have that from the expression;

dm/dt = (K * 4 * 10-8 (1 - m)) / 7 * 10-8

dm/1-m = 0.57 Kdt

integrating between limits

∫dm/1-m (0.2 to 0.77) = 0.57 ∫ dt (0 to 0.6)