In a different plan for area codes, the first digit could be any number from 0 throughnbsp 5 , the second digit was either 6, 7, 8 , and the third digit could be any number except bsp 3nbsp bsp or 4. With this plan, how many different area codes are possible?

There are 144 different area codes possible

Step-by-step explanation:

To solve this problem, we need to know how many possibilities are for each number, and them multiply them:

For the first digit, there are 6 possibilities (0,1,2,3,4,5);

For the second digit, there are 3 possibilities (6,7,8);

For the third digit, there are 8 possibilities (0,1,2,5,6,7,8,9).

So, the number of different area codes are 6*3*8 = 144