Create a pattern with the rule n*2+1

The rule (n*2+1) gives the sequence of odd numbers { ..., - 5, - 3, - 1, 1, 3, 5, ... }.

Step-by-step explanation:

We have the expression 'n*2+1'.

It is required to find a pattern obtained by the expression.

Substituting values of 'n' gives,

For n = - 3, we get (n*2+1) = (-3*2+1) = - 6+1 = - 5

For n = - 2, we get (n*2+1) = (-2*2+1) = - 4+1 = - 3

For n = - 1, we get (n*2+1) = (-1*2+1) = - 2+1 = - 1

For n = 0, we get (n*2+1) = (0*2+1) = 1

For n = 1, we get (n*2+1) = (1*2+1) = 2+1 = 3

For n = 2, we get (n*2+1) = (2*2+1) = 4+1 = 5

So, we see that, substituting the value of n, the result comes out to be an odd number.

Hence, the rule (n*2+1) gives the sequence of odd numbers { ..., - 5, - 3, - 1, 1, 3, 5, ... }.