Given a regular octagon, in how many ways can we color one diagonal red and another diagonal blue so that the two colored diagonals cross (in the interior) ? Consider rotations and reflections distinct.

Rotation = 1.

Reflection = 5 or 4.

Step-by-step explanation:

A regular octagon is the octagon that has eight, 8 sides and all these eight sides are equal.

So, if we are going to consider rotation and reflection distinct in order to color one diagonal red and another diagonal blue so that the two colored diagonals cross (in the interior) we can do that by following the steps Below;

=> Make sure that the first diagonal with the red color is drawn first.

=> to another make fixing to another end.

=> Determine the possibilities.

The numbers of times can be gotten by using Burnside Lemma which gives Rotation = 1 And Reflection = 5 or 4.