Find (g ∘ f) (10) when f (x) = and g (x) = 2x + 3.

A. 9

B. 15

C. 69

D. 22/3

See Below

Step-by-step explanation:

The equation of f (x) isn't given so I will assume one equation for f (x) and solve the problem to show the process. The answer choices won't hold.

New Problem:

Find (g ∘ f) (10) when f (x) = 3x - 1 and g (x) = 2x + 3

Solution:

The notation (g ∘ f) (10) means take the function "f" and put it into "g" and then evaluate that expression with "10". First, lets find (g ∘ f) (x).

f (x) = 3x - 1

g (x) = 2x + 3

(g ∘ f) (x) = 2 (3x - 1) + 3

= 6x - 2 + 3

= 6x + 1

So,

(g ∘ f) (x) = 6x + 1

Now,

(g ∘ f) (10) = 6 (10) + 1 = 61

This would be the answer.