The weight of oranges growing in an orchard is normally distributed with a mean

weight of 5 oz. and a standard deviation of 1 oz. Using the empirical rule, what

percentage of the oranges from the orchard weigh between 3 oz. and 7 oz.?

The percentage is 95.45%

Step-by-step explanation:

In this question, we are tasked with calculating the percentage of oranges weighing between a particular range.

To do this, we use the z-scores of both numbers in the range.

Mathematically, z-score can be calculated as (x - Mean) / SD

Thus we have P (3
= P (-2 < z < 2)

Using standard score table, we have

P (-2
The percentage is thus 9545/100 = 95.45