What is the value of r in this equation? 4 (x-3) - r+2x=5 (3x-7) - 9x

4 (x-3) - 2+2x=5 (3x-7) - 9x

4x-12-r+2x=5 (3x-7) - 9

4x-12-r+2x=15x-35-9x

6x-12-r=15x-35-9x

6x-12-r=6x-35

add 12 to - 35 which equals - 23.

add 6x+6x it cancels out to 0.

-r=-23

to make r positive just add it - 23

since 23 is already negative it would become a positive because a negative + negative = positive

answer: r=23