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23 December, 23:24

What is the maximum height for - 16t^2+96t+63

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  1. Yesterday, 00:32
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    h (3) = 207 feet

    Step-by-step explanation:

    what is the maximum height for - 16t^2+96t+63

    h (t) = - 16t^2+96t+63

    We see max height at the vertex of this parabolic function

    x = - 96/2 * (-16) = 3 seconds

    h (3) = - 16*3*3 + 96*3 + 63

    h (3) = - 144 + 288 + 63

    h (3) = 207 feet
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