Matt and Taylor are taking a test. The test is designed to produce an overall mean score of 80, with a standard deviation of 6 for all test takers. Suppose Matt scored an 85 on the test and Taylor scored a 78 on the test. Given that the data is approximately normal, find the probability that another test taker, chosen at random, scored less than Matt and more than Taylor.

Question

Mathematics

Kaufman

18 July, 15:03

Matt and Taylor are taking a test. The test is designed to produce an overall mean score of 80, with a standard deviation of 6 for all test takers. Suppose Matt scored an 85 on the test and Taylor scored a 78 on the test. Given that the data is approximately normal, find the probability that another test taker, chosen at random, scored less than Matt and more than Taylor.

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Answers (1)

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Pixie Stick · Answer 1

P (r) = 1/3

Step-by-step explanation:

Matt 85 - 80 = + (5)

Taylor 80-78 = - (2)

+5-2 = 3 rise so deviation is the same.

Another test taker in 4 outcomes less than taylor more than taylor less than matt more than matt, would also be the same as AnB union.

So their are 3 outcomes = 1/3 = 0.333 rep.