Ask Question
29 December, 14:49

Write a polynomial function of least degree with integral coefficients that have the given zeros. 4,-1,6 f (x) = x^3-9x^2+14x+24

+3
Answers (1)
  1. 29 December, 16:57
    0
    see explanation

    Step-by-step explanation:

    Given the zeros of a polynomial, say x = a, x = b, x = c

    Then (x - a), (x - b), (x - c) are it's factors

    and the polynomial is the product of the factors

    here x = 4, x = - 1, x = 6, hence

    (x - 4), (x + 1) and (x - 6) are the factors

    f (x) = a (x - 4) (x + 1) (x - 6) ← a is a multiplier

    let a = 1, then expanding the first pair of factors

    f (x) = (x² - 3x - 4) (x - 6) ← expand out the factors

    = x³ - 3x² - 4x - 6x² + 18x + 24 ← collect like terms

    = x³ - 9x² + 14x + 24
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Write a polynomial function of least degree with integral coefficients that have the given zeros. 4,-1,6 f (x) = x^3-9x^2+14x+24 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers