On June 1, 2007, there were about 18.75 h of daylight in Anchorage,

Alaska. On November 1, 2007, there were about 8.5 h of daylight. What was the

percent decrease?

Question

Mathematics

Ramiro Reese

14 June, 17:35

On June 1, 2007, there were about 18.75 h of daylight in Anchorage,

Alaska. On November 1, 2007, there were about 8.5 h of daylight. What was the

percent decrease?

+1

Answers (1)

Know the Answer?

Saul Le · Answer 1

The percent decrease of daylight on November 1,2007 is 54.67.

Step-by-step explanation:

While finding the difference between 18.75 and 8.5 is about 10.25h. Percentage gives right value of increase and decrease in value. It is easier to calculate and understand percentage wise. It is imperative to start percentage by 10%,5% and 1%. While taking 10% of 18.75 it comes to 1.875. If we take 5 times of 10% it comes too 9.375h. It is very closer to 10.25h. If you take 5% it goes approximately beyond 10.25h. It is imperative to take less then 4% 0.75 it comes to 10.125h. If we take 1% 0.1875 which is again beyond 10.25h. It is important to take exactly 10.25h. If we take less then 1% about 0.67%. It is closer to 10.25h. 10% of 5 times 9.375 4% 0.75 and 0.67.

On June 1, 2007, there were about 18.75 h of daylight in Anchorage,Alaska. On November 1, 2007, there were about 8.5 h of daylight. What was thepercent decrease?

On June 1, 2007, there were about 18.75 h of daylight in Anchorage,

Alaska. On November 1, 2007, there were about 8.5 h of daylight. What was the

percent decrease?