What is angle A on a right triangle with sides AB being 6 and side CB being 4

Answer:41.8

Step-by-step explanation:

a=4

c=6

C=90

Applying sine rule:

a/sinA = c/sinC

4/sinA=6/sin90 sin90=1

4/sinA=6/1

Cross multiplying we get

4 x 1=6 x sinA

4=6sinA

divide both side by 6

4/6 = (6sinA) / 6

4/6=sinA

sinA=4/6

A=sin (inverse) (4/6)

A=41.8