How do you solve 6x^2 + 12x-48=0 by completing the square?

x = - 4 and x = 2

Through the Completing the Square process below:

Step-by-step explanation:

solve 6x^2 + 12x-48=0

first divide out the 6

x^2 + 2x - 8 = 0

Then use the Diamond method:

-8 = - 2*4, and - 2 + 4 = 2

so

x^2 - 2x + 4x - 8 = 0

x (x - 2) + 4 * (x - 2) = 0

(x + 4) (x - 2) = 0

so, solve x + 4 = 0 and (x - 2) = 0

x = - 4 and x = 2