Find the number of real solutions of the equation x^2+10x+35=0 using the discriminant: (b^2-4ac)

Answer: No real roots or solutions

Step-by-step explanation:

X^2+10x+35=0 using this equation you can tell that a=1, b=10, and c=35. Using the numbers for the formula,

b^2 - 4ac, it will look like this ... 10^2-4 (1) (35). Next step is the exponent. It will look like this now, 100-4 (1) (35), the next step is to multiply. 100-140 = - 40. When the discriminant is negative, there are no real roots, or solutions.