The sum of three consecutive odd integers is 27. Which equation represents the situation

A) x + (x+1) + (x+2) = 27

B) x + (x+2) + (x+4) = 24

C) x + (x+1) + (x+3) = 27

Well when i worked out A. I got 8,9 and 11 when you add them you get 27.

When i worked out B i got 6,8 and 12 when added i got 26

For C i got a decimal. So I'd go with A but 8 isn't odd.

To solve you combine like terms so add all of the x's. You'll get 3x + 6=27 subtract the 6 then divide by 3. You'll get 8 then add 1. Add 2 to 9 you'll get 11.

None of these answers id correct.

The three consecutive odd integers would be: (2x+1), (2x+3) and (2x+5), and the correct equation would be:

(2x+1) + (2x+3) + (2x+5) = 27

6x+9=27

6x=27-9

6x=18

x=18/6

x=3

The numbers would be:

2x+1=2 (3) + 1=7

2x+3=2 (3) + 3=9

2x+5=2 (3) + 5=11

Answer: the correct equation would be: (2x+1) + (2x+3) + (2x+5) = 27; and the numbers would be: 7,9 and 11.