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28 July, 08:19

Find all the solutions of sin x + cos x = 1 in the interval [0, 2pie).

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  1. 28 July, 08:59
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    X = 0, π/2 in the interval [0, 2pi).

    Step-by-step explanation:

    Use the auxiliary angle method:

    R sin (x + a) = Rsin x cos a + Rcos x sin a = 1

    sin x + cos x = 1

    Comparing coefficients:

    R cos a = 1 and R sin a = 1, so

    tan a = R sin a / R cos a = 1

    So a = π/4 radians.

    Also R^2 (sin^2 a + cos^2 a) = 1^2 + 1^2 = 2

    Therefore R = √2.

    So √2 sin (x + π/4 = 1

    sin x + π/4 = 1/√2

    x + π/4 = π/4

    x = 0 radians

    Also

    x = 0 + π/2 = π/2.
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