Trigonometry

Trigonometric Equations

csc x cot x + cot x = 0; x [ 0, 2π ]

Question

Mathematics

Bronson

2 February, 09:14

Trigonometry

Trigonometric Equations

csc x cot x + cot x = 0; x [ 0, 2π ]

+4

Answers (2)

Know the Answer?

Julius Hodge · Answer 1

x=π/2,3π/2

Step-by-step explanation:

cot x (csc x+1) = 0

either cot x=0

tanx=∞=tan (π/2)

x=π/2

or csc x=-1

or sin x=-1=-sin (π/2) = sin (π+π/2) = sin (3π/2)

x=3π/2

Rubi Compton · Answer 2

x = π/2, 3π/2

Step-by-step explanation:

cosecxcotx + cotx = 0

cotx (cosecx + 1) = 0

cotx = 0

x = π/2,

π + π/2 = 3π/2

cosecx = - 1

x = 3π/2

x = π/2, 3π/2

TrigonometryTrigonometric Equationscsc x cot x + cot x = 0; x [ 0, 2π ]

Trigonometry

Trigonometric Equations

csc x cot x + cot x = 0; x [ 0, 2π ]