Find the equation of a line that runs through (-2,5) and is perpendicular tot he line defined by - x-6y=-24

Answers:

y+5=6 (x-2)

y+2=6 (x-5)

y-5=6 (x+2)

Make the equation into y=mx+b form

y=-x/6 + 24

The slope is - 1/6, so the slope for the perpendicular line is the opposite reciprocal which is positive 6.

y=6x+b

Solve for b using substitution with the coordinates

5=6 (-2) + b

b=17

y=6x+17, or y-5=6 (x+2)