The sum of four consecutive integers is 266. What are the integers?

The 4 consecutive integers are 65,66,67,68

Step-by-step explanation:

Ok so there are 4 different numbers and they are consecutive, so you'd start of like:

266 = n + (n+1) + (n+2) + (n+3). Next you would collect like terms to simplify ...

266=4n+6. Next you want to solve for n ...

266-6=4n+6-6

260=4n

260/4=4n/4

65=n ... so you have n. hurray, but you need the other three numbers ... so just substitute 65 as n in the formula:

266=65 + (65+1) + (65+2) + (65+3)

266=65+66+67+68

266=266 both sides are equal so it means the equation is solved. The 4 consecutive integers are 65,66,67,68

Let the four consecutive integers are x, x + 1, x + 2, x + 3.

According to the question,

Sum of four consecutive integers = 266. [ Given ]

⇒ x + x + 1 + x + 2 + x + 3 = 266

⇒ 4x + 6 = 266

⇒ 4x = 260

⇒ x = 260/4

⇒ x = 65

Integers are:

x = 65

x + 1 = 65 + 1 = 66

x + 2 = 65 + 2 = 67

x + 3 = 65 + 3 = 68