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8 April, 16:11

What are the factors of x2 - 64?

A. Prime

B. (x - 4) (x + 16)

C. (x - 8) (x - 8)

D. (x + 8) (x - 8)

+4
Answers (1)
  1. 8 April, 18:16
    0
    X^2 - 64 uses the algebraic identity of a^2 - b^2

    so x^2 - 64 = x^2 - 8^2 = (x - 8) (x + 8)

    thus the answer should be D (not sure if i'm correct!)
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