What is the zero of the function f (x) = 1/8x^2-x+2

x = 4

Step-by-step explanation:

ƒ (x) = ⅛x² - x + 2 = 0

x² - 8x + 16 = 0

We must find two numbers whose product is 16 and whose sum is - 8.

A little trial and error gives us - 4 and - 4. We can factor the expression as

(x - 4) (x - 4) = 0 or

(x - 4) ² = 0

x - 4 = 0

x = 4

The zero of the function is x = 4.

The graph of ƒ (x) just touches the x-axis at (4, 0).