Kiran graphed the equation

y = x^2 + 1 and noticed that the vertex is at (0, 1). He changed the equation to

y = (x - 3) ^2 + 1 and saw that the graph shifted 3 units to the right and the vertex is now at (3,1).

Next, he graphed the equation y = x^2 + 2x + 1, observed that the vertex is at (-1, 0). Kiran thought if i change the squared term x^2 to (x-5) ^2, the graph will move 5 units to the right and the vertex will be at (4,0)." do you agree with kiran explain or show your reasoning.

Question

Mathematics

Emerson Bridges

16 October, 23:36

Kiran graphed the equation

y = x^2 + 1 and noticed that the vertex is at (0, 1). He changed the equation to

y = (x - 3) ^2 + 1 and saw that the graph shifted 3 units to the right and the vertex is now at (3,1).

Next, he graphed the equation y = x^2 + 2x + 1, observed that the vertex is at (-1, 0). Kiran thought if i change the squared term x^2 to (x-5) ^2, the graph will move 5 units to the right and the vertex will be at (4,0)." do you agree with kiran explain or show your reasoning.

+5

Answers (2)

Know the Answer?

Aryanna Reeves · Answer 1

I agree with Kiran

William Lester · Answer 2

You agree with Kiran

Step-by-step explanation:

As seen in the first example, when you subtract a number from the X variable the amount taken away from it, called an horizontal transition. If the number was added then it would have been shifted to the right.