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18 August, 21:53

Find all of the solutions for the following equation. 2 sin q + 3 = sin q + 2

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  1. 19 August, 01:02
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    q = 270 degrees + 360n where n is an integer

    Step-by-step explanation:

    2 sin q + 3 = sin q + 2

    Subtract sin q from each side

    2 sin q - sin q + 3 = sin q + 2

    sin q + 3 = 2

    Subtract 3 from each side

    sin q + 3-3 = 2-3

    sin q = - 1

    Take the inverse sin of each side

    sin ^-1 (sin q) = sin^-1 (-1)

    q = 270 degrees + 360n where n is an integer
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