Find all of the solutions for the following equation. 2 sin q + 3 = sin q + 2

q = 270 degrees + 360n where n is an integer

Step-by-step explanation:

2 sin q + 3 = sin q + 2

Subtract sin q from each side

2 sin q - sin q + 3 = sin q + 2

sin q + 3 = 2

Subtract 3 from each side

sin q + 3-3 = 2-3

sin q = - 1

Take the inverse sin of each side

sin ^-1 (sin q) = sin^-1 (-1)

q = 270 degrees + 360n where n is an integer