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18 August, 03:33

What are the solutions for the equation x^6+6x^3+5=0? Use factoring to solve

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  1. 18 August, 03:55
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    Step-by-step explanation:

    Don't be fooled by this. We can make this look like the equations you have been factoring up to now. Let

    x^3 = y Square both sides of the equation

    (x^3) ^2 = y^2

    x^6 = y^2

    Now substitute these results into the given equation.

    y^2 + 6y + 5 = 0

    This factors

    (y + 5) (y + 1) = 0

    So either y + 5 = 0

    or y + 1 = 0

    y+5 = 0

    x^3 + 5 = 0

    x = cuberoot (-5)

    x^3 + 1 = 0

    x^3 = - 1

    cube root (x^3) = cube root (-1)

    x = - 1

    Essentially the graph shows that there are only 2 roots (-1,0) (-1.71,0) just as our solution suggests.
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