Consider this system of equations. Which shows the first equation written in slope-intercept form?

2 (2y+10) = 7*

y=8

y = 7x-10

7

y=zx-5

y = 7x-5

o y = 1 x - 5

Question:

Consider this system of equations. Which shows the first equation written in slope-intercept form?

½ (2y + 10) = 7x.

y = 8.

A. y = 7x - 10

B. y = 7x/2 - 5

C. y = 7x - 5

D. y = 7x/4 - 5

Answer:

C. y = 7x - 5

Step-by-step explanation:

Given

½ (2y + 10) = 7x.

Required

Convert to slope intercept form.

To do this, we simply make y the subject of formula from the given equation

We start by writing out the equation

½ (2y + 10) = 7x.

Then, we open the bracket

½ * 2y + ½ * 10 = 7x

2y/2 + 10/2 = 7x

y + 5 = 7x

Then, subtract 5 from both sides of the equation

y + 5 - 5 = 7x - 5

y = 7x - 5

The equation can't be simplified any further. So, we've arrived at a solution

Hence, the slope intercept form of ½ (2y + 10) = 7x is y = 7x - 5