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23 October, 10:25

The center of a circle is located at (3,8), and the circle has a radius that is 5 units long. What is the general form of the equation for the circle?

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A. x2 + y2 - 6x - 16y + 48 = 0

B. x2 + y2 - 6x - 16y - 25 = 0

C. x2 + y2 + 6x + 16y + 48 = 0

D. x2 + y2 + 6x + 16y - 25 = 0

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  1. 23 October, 13:12
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    answer: A x²-6x+y²-16y + 48=0

    Step-by-step explanation:

    hello:

    the standard form is : (x-3) ² + (y-8) ² = 25

    x²-6x+9 + y²-16y+64 = 25

    x²-6x+y²-16y + 48=0
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