If n = 8 and 16 · 2^m = 4^ (n - 8), then m = ?

F. - 4

G. - 2

H. 0

J. 1

K. 8

Question

Mathematics

Tyson

15 April, 14:43

If n = 8 and 16 · 2^m = 4^ (n - 8), then m = ?

F. - 4

G. - 2

H. 0

J. 1

K. 8

+3

Answers (1)

Know the Answer?

Sutton · Answer 1

16 · 2^m = 4^ (n - 8)

get everything with the same base)

2^4 * 2^m = 2^2^ (n-8)

2^ (4+m) = 2^ (2 (n-8))

4+m = 2 (n-8)

4+m = 2n-16

m = 2n-16-4

if n=8

m = 2n-20

m = 16-20

m=-4

Choice F

If n = 8 and 16 · 2^m = 4^ (n - 8), then m = ?F. - 4G. - 2H. 0J. 1K. 8

If n = 8 and 16 · 2^m = 4^ (n - 8), then m = ?

F. - 4

G. - 2

H. 0

J. 1

K. 8