Use any method for solve the following equation for x. 0=x^2+3x-18

I am going to use factorization

0=

x^2+3x-18

0 = (x-3) (x+6)

6x-3x-18

0 = x^2+3x-18

I am just double checking to see if my factorization is right first.

(x-3) (x+6) = 0

x-3+3 = 0+3

x = 3

x+6=0

x+6-6=0-6

x=-6

Answer : x=3, x=-6