The guayule plant, which grows in the southwestern United States and in Mexico, is one of several plants that can be used as a source of rubber. In a large group of guayule plants, the heights of the plants are normally distributed with a mean of 12 inches and a standard deviation of 2 inches. a. What percent of the plants are taller than 16 inches? $/%$ b. What percent of the plants are at most 13 inches? $/%$ c. What percent of the plants are between 7 inches and 14 inches? $/%$ d. What percent of the plants are at least 3 inches taller than or at least 3 inches shorter than the mean height? $/%$

The correct answer to the question for (a) the percentage of the plants which are taller than 16 inches is 2.28 % (b) the percent of the plants are at most 13 inches is 69.15% (c) the percent of the plants that are between 7 inches and 14 inches is 83.51% (d) the percent of the plants that are at least 3 inches taller than or at least 3 inches shorter than the mean height is 1

Step-by-step explanation:

Solution

Recall that

(a) μ = 12 and б = 2

Then,

Z = x - μ/б

= 16 - 12 / 2 = 2

thus,

1-p (z<2) = 1 - 0.9772 = 0.0228

= 2.28 %

Therefore the percentage of the plants which are taller than 16 inches is 2.28 %

(b) Z = 13-12/2

which is = 0.5

p (z<0.5) = 0.6915

=69.15%

Therefore the percent of the plants are at most 13 inches is 69.15%

(c) we calculate for the percent of the plants that are between 7 inches and 14 inches

Now,

p (7
p = (-2.5
which is, = 0.8351

=83.51%

(d) What percent of the plants are at least 3 inches taller than or at least 3 inches shorter than the mean height

Now,

Z = x - μ/б = 3-12/2 = - 4.5

Thus,

p (z>-4.5) = p (z>-4.5)

= 1