A training field is formed by joining a rectangle and two semicirces, as shown below. The rectangle is 94 m long and 60 m wide.

Find the area of the training field. Use the value 3.14 for y, and do not round your answer. Be sure to include the correct unit in your answer.

Question

Mathematics

Luciano Meadows

8 October, 02:31

A training field is formed by joining a rectangle and two semicirces, as shown below. The rectangle is 94 m long and 60 m wide.

Find the area of the training field. Use the value 3.14 for y, and do not round your answer. Be sure to include the correct unit in your answer.

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Answers (1)

Know the Answer?

Rayan Mcfarland · Answer 1

8466

Step-by-step explanation:

The semi-circles form an entire circle with diameter of 60.

The radius is 30.

Area of the rectangle is 94 x 60=5640.

Area of the circle is 3.14 x 30 x 30=2826

Total area is 5640+2826=8466

A training field is formed by joining a rectangle and two semicirces, as shown below. The rectangle is 94 m long and 60 m wide.Find the area of the training field. Use the value 3.14 for y, and do not round your answer. Be sure to include the correct unit in your answer.

A training field is formed by joining a rectangle and two semicirces, as shown below. The rectangle is 94 m long and 60 m wide.

Find the area of the training field. Use the value 3.14 for y, and do not round your answer. Be sure to include the correct unit in your answer.