Mathematics

Piggy

15 March, 09:17

Select from the drop-down menus to correctly complete the proof.

To prove that 3√2 is irrational, assume the product is rational and set it equal to a/b , where b is not equal to 0: 3√2=a/b. Isolating the radical gives √2=a/3b. The right side of the equation is choose (rational or irrational). Because the left side of the equation is choose (rational or irrational), this is a contradiction. Therefore, the assumption is wrong, and the number 3√2 is choose (rational or irrational).