In a cash drawer there is $125 in $5 and $10 bills. The number of $10 bills is twice the number of $5 bills. How many of each type of bill is in the drawer?

Let us take number of $5 bills = x and

number of $10 bills = y.

Give that "number of $10 bills is twice the number of $5 bills".

So, y is twice of x,

We can setup an equation.

y = 2x ... equation (1)

Total value of all bills = $125.

We can setup another equation,

5 * (number of $5 bills) + 10 * (number of $10 bills) = 125.

5 (x) + 10 (y) = 125 ... equation (2)

Plugging y=2x in equation (2), we get

5 (x) + 10 (2x) = 125.

5x+20x = 125.

Adding like terms

25x = 125

Dividing both sides by 25.

25x / 25 = 125/25

x = 5.

Plugging x=5 in first equation, we get

y = 2 (5) = 10.

Therefore, number of number of $5 bills=5 bills and number of $10 bills = 10 bills.