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6 September, 03:58

Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels 20 miles per hour slower than the westbound train. If the two trains are 800 miles apart after 4 hours, what is the rate of the eastbound train?

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  1. 6 September, 05:36
    0
    Let x be the speed of eastbound train

    The eastbound train travels 20 miles per hour slower than the westbound train.

    so the speed of westbound train is x + 20

    Distance = speed * time

    Time = 4 hours

    Distance traveled by each bound train = 4x

    Distance traveled by westbound train = 4 (x+20)

    Two trains are 800 miles apart

    4x + 4 (x+20) = 800

    4x + 4x + 80 = 800

    8x + 80 = 800

    Subtract 80 from both sides

    8x = 720

    Divide both sides by 8

    x = 90

    The speed of east bound train is 90 miles per hour
  2. 6 September, 07:03
    0
    90 mph

    Step-by-step explanation:

    Let the speed of the westbound train (A) be x mph; and

    the speed of the eastbound (B) train be (x-20) mph.

    We know that distance = speed x time

    so distance traveled by A = 4x; and

    the distance traveled by B = 4 (x - 20) = 4x - 80.

    Adding these distances up to get:

    4x + (4x - 80) = 800

    4x + 4x = 800 - 80

    8x = 720

    x = 720/8

    x = 90

    Therefore, the rate at which the eastbound train travels is 90 mph.
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