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29 March, 18:06

your 2500 gallon pool has sprung a leak and loses 70% of its water every 10 minutes. how much water will remain in the pool after 30 minutes. what is the equation and answer

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  1. 29 March, 21:14
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    equation : water remaining in pool after 30 mins = 0.027X

    answer = 67.5 Gallon

    Step-by-step explanation:

    Given

    quantity of water in pool = 2500 gallon

    percentage of water lost every 10 mins = 70%

    therefore percentage of water remaining in pool = (100 - 70) % = 30%

    Let the quantity of water in pool be X gallon

    % of water remaining in gallon after 10 mins = 30% of X = 0.3X

    % of water remaining in gallon after another 10 mins = 30% of water at 10 mins = 30% of 0.3 X = 0.3 * 0.3X = 0.09 X

    % of water remaining in gallon after another 30 mins = 30% of water present at 20 minutes = 30% of 0.09 X = 0.3 * 0.09X = 0.027X

    Therefore equation of water remaining after 30 mins is = 0.027 X

    Substituting value of initial quantity of water in the above equation we get the volume pf water remaining in pool after 30 mins = 0.027 * 2500

    = 67.5 gallons
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