A certain television is advertised as a 58-inch TV (the diagonal length). If the width of the TV is 42 inches, how many inches tall is the TV?

Your answer will be 16

The height of the television is:

40 inches.

Step-by-step explanation:

To solve the proposed exercise you must understand two things:

Since the flat figure of a television is a rectangle, it can be subdivided into a right triangle (since it has at least a 90 ° angle) A variation of the Pythagorean Triangle will be used.

The Pythagorean triangle tells us that the sum of the base squared and the height squared of a right triangle will be equal to the hypotenuse (diagonal) squared of the triangle, which is usually expressed like this:

a^2 + b^2 = c^2

But to make it more understandable, let's express it like this:

base^2 + height^2 = diagonal^2

Since the diagonal and the base (width) of the television are provided in the exercise, we must clear the height and calculate:

height^2 = diagonal^2 - base^2 height^2 = 58^2 - 42^2 height^2 = 1600

To identify the value if in the square, you must apply square root to the obtained value:

height^2 = square root of 1600 height^2 = 40 inches.