There are nine players on a baseball team. How many different batting lineups are possible

Question

Mathematics

Christina Ingram

24 October, 07:09

There are nine players on a baseball team. How many different batting lineups are possible

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Answers (2)

Know the Answer?

Kathy Moyer · Answer 1

362,880

Step-by-step explanation:

9*8*7*6*5*4*3*2*1=362,880. You multiply the number of players, but subtract one each time.

Siena Benitez · Answer 2

Answer: 362,800

Step-by-step explanation: To determine how many different batting orders are possible for a 9-player softball team, let's start by drawing 9 blanks to represent the 9 spots in the order.

We know that 9 different players can fill the first spot in the order. However, once the first spot is filled, there are only 8 players left to fill the second spot and once the second spot is filled, there are only 7 players left to fill the third spot and so on.

Therefore, based on the counting principal, we have 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 ways for all 9 spots to be filled which simplifies to 362,880.

Therefore, there are 362,880 different batting orders for a 9-player softball team.