the perimeter of a rectangle 310m the lenght is 25m greater than the width what are the length and width of a rectangle

Let x be the width.

length is 25m greater than the width, hence, x+25 will represent the length.

perimeter is 310m

W=x

L = x+25

Solution:

P=2 (L+w)

310m=2[ (x+25m) + x) ]

combine like terms

310m=2 (2x+25m)

310m=4x+50m

transpose

310m-50m=4x

260m=4x

divide both sides by 4

65 = x

now that we have the measurement of the width. get the measurement of the length

Length = x+25m

L=65m+25m

L=90m