What are the zeros of the function? f (b) = b ^2 - 16b + 64

b = 8 and b = 8

Step-by-step explanation:

f (b) = b² - 16b + 64 is set equal to zero and solved for b:

f (b) = b² - 16b + 64 = 0

This quadratic can be factored, as follows: f (b) = (b - 8) (b - 8) = (b - 8) ² = 0

There are two real, equal zeros: b = 8 and b = 8.