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13 December, 04:55

Solve 4n+2mn=3mn ² for m.

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  1. 13 December, 05:59
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    m = sqrt (4 / (3 n) + 1 / (9 n^2)) + 1 / (3 n) or m = 1 / (3 n) - sqrt (4 / (3 n) + 1 / (9 n^2))

    Step-by-step explanation:

    Solve for m:

    4 n + 2 m n = 3 m^2 n^2

    Subtract 3 m^2 n^2 from both sides:

    4 n + 2 m n - 3 m^2 n^2 = 0

    Divide both sides by - 3 n^2:

    m^2 - 4 / (3 n) - (2 m) / (3 n) = 0

    Add 4 / (3 n) to both sides:

    m^2 - (2 m) / (3 n) = 4 / (3 n)

    Add 1 / (9 n^2) to both sides:

    m^2 + 1 / (9 n^2) - (2 m) / (3 n) = 4 / (3 n) + 1 / (9 n^2)

    Write the left hand side as a square:

    (m - 1 / (3 n)) ^2 = 4 / (3 n) + 1 / (9 n^2)

    Take the square root of both sides:

    m - 1 / (3 n) = sqrt (4 / (3 n) + 1 / (9 n^2)) or m - 1 / (3 n) = - sqrt (4 / (3 n) + 1 / (9 n^2))

    Add 1 / (3 n) to both sides:

    m = sqrt (4 / (3 n) + 1 / (9 n^2)) + 1 / (3 n) or m - 1 / (3 n) = - sqrt (4 / (3 n) + 1 / (9 n^2))

    Add 1 / (3 n) to both sides:

    Answer: m = sqrt (4 / (3 n) + 1 / (9 n^2)) + 1 / (3 n) or m = 1 / (3 n) - sqrt (4 / (3 n) + 1 / (9 n^2))
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