Ask Question
13 February, 10:59

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $65. For one performance, 15 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $1150. What was the price of each kind of ticket?

+3
Answers (1)
  1. 13 February, 13:02
    0
    Advance tickets cost $30; same-day tickets cost $35.

    Step-by-step explanation:

    Let a = the cost of an advance ticket

    and s = the cost of a same-day ticket

    We have two conditions:

    (1) a + s = 65

    (2) 15a + 20s = 1150

    Subtract a from each side of (1) (3) s = 65 - a

    Substitute (3) into (2) 15a + 20 (65 - a) = 1150

    Distribute the 20 15a + 1300 - 20a = 1150

    Combine like terms 1300 - 5a = 1150

    Subtract 1300 from each side - 5a = - 150

    Divide each side by - 5 (4) a = 30

    Substitute (4) into (1) 30 + s = 65

    Subtract 30 from each side s = 35

    Advance tickets cost $30; same-day tickets cost $35.

    Check:

    (1) 30 + 35 = 65 (2) 15 * 30 + 20 * 35 = 1150

    65 = 65 450 + 700 = 1150

    1150 = 1150
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers