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24 October, 00:04

Are the following equivalent: 7+7x; 7 x + 1/7

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  1. 24 October, 01:52
    0
    not equivalent

    Step-by-step explanation:

    7+7x

    Subtract what we think is equivalent and we should get 0

    7+7x - (7x+1/7)

    7+7x - 7x - 1/7

    7 - 1/7

    Get a common denominator

    49/7 - 1/7

    48/7

    This is not 0
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