What are the real zeros in f (x) = x^3+8

Question

Mathematics

Elsa Dominguez

8 February, 12:45

What are the real zeros in f (x) = x^3+8

+2

Answers (2)

Know the Answer?

Kayley Cabrera · Answer 1

X = - 2

Step-by-step explanation:

X^3 + 8 = 0

X^3 = - 8

X = - 8 ^ (1/3)

X = - 2

Hubbard · Answer 2

-2

Step-by-step explanation:

f (x) = x^3+8

Set it equal to 0

0 = x^2 + 8

Subtract 8 from each side

-8 = x^3+8-8

-8 = x^3

Take the cube root of each side

-8 ^ 1/3 = x^3 ^ 1/3

-2 = x

The only real root is - 2